rasionalkanlah 4/7-√3
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Penjelasan dengan langkah-langkah:
[tex] = \frac{4}{7 - \sqrt{3} } [/tex]
[tex] = \frac{4}{7 - \sqrt{3} } \times \frac{7 + \sqrt{3} }{7 + \sqrt{3} } [/tex]
[tex] = \frac{4.(7 + \sqrt{3} )}{ {7}^{2} - \sqrt{ {3}^{2} } } [/tex]
[tex] = \frac{4.(7 + \sqrt{3} )}{49 - 3} [/tex]
[tex] = \frac{4.(7 + \sqrt{3}) }{46} [/tex]
[tex] = \frac{2.(7 + \sqrt{3} )}{23} [/tex]
[tex] = \frac{14 + 2 \sqrt{3} }{23} [/tex]
[answer.2.content]
